objective to find out the emf of an unknown battery using potentiometer let us look at how a potentiometer is used to measure the emf of a battery we know that balancing equation for a potentiometer is b equals to v naught l by l naught where v is the potential difference across the terminals of the potentiometer l is the balancing length v naught is the potential drop across a b and l naught is the length of the wire a b

suppose the terminals of the potentiometer are connected across a battery with emf e at null deflection point the current through the battery is zero and the voltage difference across lm is equal to emf of the battery by identifying the corresponding length and substituting it in the balancing equation the emf of the cell can be measured accurately

one easy way of finding the emf of an unknown battery is to compare it with a standard battery of known emf two batteries one of known emf e1 and another of unknown emf e2 are connected to potentiometer using a two-way key as shown the driving circuit should have a strong battery so that the potential difference across a b is larger than the emf of the two batteries when the key is plugged in s1 the first battery gets connected to the driving circuit when the key is taken out and pressed into the other plug s2 the first battery gets disconnected and the second battery gets connected when the key is plugged into s1 the jockey is slid to find the null deflection point p1 on the wire a b let the balancing length ap1 be l1 e1 is equal to v naught into l1 by l naught where l naught is the length of a b and v naught is the potential difference across it key is taken out and gets inserted into s2 let null deflection occur at a point p2 this time let the balancing length ap2 be l2 e2 is equal to v naught into l2 by l naught upon dividing the two equations we get e2 by e1 equals to l2 by l1 the unknown emf e2 is equal to e1 into l2 by l1

for example in a potentiometer arrangement a battery of emf e1 equal to 5 volts gives a balance point at l1 equal to 240 centimeters now when an unknown battery is connected the balance point shifts to l2 equal to 360 centimeters then the unknown emf e2 is given by the relation e2 is equal to e1 into l2 by l1 thus e2 equals to 5 into 360 by 240 which comes out to be 7.5 volts

summary emf of an unknown battery e2 is equal to emf of a standard battery e1 into balancing length of unknown battery l2 by balancing length of the known battery

Wave Propagation Demonstration

In this video, we'll discuss the periodic table of elements. A chart called the periodic table of the elements organizes all of the known elements. Rows in the periodic table are called periods, and columns are called groups or families. A section from each of the two bottom periods has been pulled out and placed below the table to avoid making the table too wide. The elements are organized left to right and top to bottom by their atomic number, meaning the number of protons in one atom of the element. Each box shows an element represented by its unique symbol. The smaller number next to each element's symbol represents the atomic number. The atomic number increases by one as you go from left to right across each period. The larger number represents the atomic mass. Notice that the atomic mass of many elements is a decimal number rather than a whole number. This is because the atomic mass is a weighted average of the mass numbers for the isotopes of an element. A weighted average takes into account how common each isotope of an element is in nature. The most common isotope counts for much more in the average than less common isotopes, just like a final exam may count more than quizzes towards your grade in a class. Notice that the atomic mass isn't the same as mass number, which is simply the total number of protons and neutrons in the nucleus of a particular isotope. However, you can determine the mass number of an element's most common isotope by rounding its atomic mass up or down to the nearest whole number. You can do this because the most common isotope has the most influence on the atomic mass. Round up if an element's atomic mass ends in .5 or greater, round down if an element's atomic mass ends in less than .5. Let's look at some examples from the periodic table. Helium has an atomic mass of 4.003. We can easily round that down to get a mass number of 4. We can also see that helium's atomic number is 2, which means it has 2 protons. Now, we can subtract the atomic number from the mass number to see that the most common isotope of helium has 2 neutrons. In the case of oxygen, we can round its atomic mass up to get a mass number of 16. Since its atomic number is 8, we know oxygen has 8 protons. And by simple subtraction, we can determine oxygen also has 8 neutrons. How does this work in a less common isotope of an element, such as hydrogen-3? The most common hydrogen isotope is hydrogen-1, as you can see from rounding the atomic mass listed in the periodic table. Recall that isotopes are identified by their mass number. So, we know hydrogen-3's mass number is 3. So, we can subtract hydrogen's atomic number of 1 from its mass number and see that hydrogen-3 has 2 neutrons. In summary, the periodic table is an organization chart of all the known elements. Each element is represented by its symbol, atomic number, and atomic mass. Elements are arranged left to right and top to bottom by increasing atomic number. An element's atomic mass is a weighted average of its isotope's mass numbers. Round the element's atomic mass up or down to find the mass number of its most common isotope.

Adrenaline 3d Animation